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S.No Question Option A Option B Option C Option D Answer Solution Comments Status Action
1 An helical spring has coil diameter 50 mm and is subject to axial load W. Another spring has coil diameter 25 mm, but otherwise identical to the first. The deflection of second spring will be _______ of that of first spring. 1/2 1/4 1/8 none of these c For closed coil helical spring
Deflection under load = \(δ\) \(\frac{8WD^{3}n}{Gd^{4}}\)
D1 = 50, D2 = 25
Since, \(δ\) \(α (D)^{3}\)
= \(\frac{δ_{2}}{δ_{1}} = (\frac{D_{2}}{D_{1}})^{3}\) \(\frac{1}{8}\)		 Comments Active
2 The behavior of mild steel under creep is a result of ______ strain hardening annealing both A & B none of these c Comments Active
3 Thermal stress in a material is proportional to elastic modulus coefficient of expansion temperature difference all of these d Comments Active
4 ABC analysis is a tool for ______management. inventory scheduling quality process a Comments Active
5 A circle will appear in an drawing as _____ circle hyperbola parabola ellipse d Comments Active
6 Which one is an attribute control chart? X P R None of these b Comments Active
7 ______maintenance requires monitoring plant equipment health. Preventive Scheduled Predictive Break down c Comments Active
8 1HP = kW 0.554 0.653 0.735 none of these c Comments Active
9 Fuel cell runs on methane nitrogen petrol hydrogen d Comments Active
10 Line balancing is imperative in _____production. batch mass job none of these b Comments Active
11 Resistance of a material to fatigue is indicated by elastic limit limit of proportionality endurance limit none of these c Comments Active
12 A 4-pole 50 Hz induction motor runs at 1455 rpm. What is the slip speed? 55 rpm 50 rpm 45 rpm none of these c Synchronous speed is given by
Where N number of poll = 4, frequency = 50 Hz
Ns = = = 1500rpm \(\frac{120×f}{p}\) \(\frac{120×50}{4}\)
Slip speed Ns - Nf = 1500 - 1455 = 45 rpm		 Comments Active
13 Break even analysis considers _______cost. fixed variable fixed and variable no c Comments Active
14 For maximum efficiency, the intermediate, P2, in stage reciprocating compressor should be (P1+P3)/2 (P3-P1)/2 \(√(P_{1}×P_{3})\) c Comments Active
15 Operating Characteristic (OC) curve shows probability of acceptance Vs. Fraction ____-. acceptable rejection defective none of these c Comments Active
16 When an orifice for flow measurement in a pipe is replaced by a venturimeter, the pressure drop for the same flow is expected to remain same increase decrease none of these c Comments Active
17 A weight of 200N is to be pulled over a surface with coefficient of friction 0.2. What is the force needed to start motion? 1000N 40 N 200.2 N 199.2 N b P = R = 0.2 200 = 40N \(μ×\) \(×\) Comments Active
18 Efficiency of induction motors can be about 50-90% 95-98% 99% 80-90% d Comments Active
19 As per Avogadro’s law, volume of 1 kmol of any gas is ___m3 at N.T.P. 22.413 8.314 273.15 none of these a Comments Active
20 Large Reynold’s number is an indication of Streamline flow Steady flow Laminar flow Highly Turbulent flow d Comments Active
21 Choose the odd-one out Solar Wind Ocean thermal Coal d Comments Active
22 Human heart is a _____pump. reciprocating pump positive displacement pump centrifugal pump none of these b Comments Active
23 A nozzle is said to be chocked when it discharges to atmosphere it is plugged it’s flow is maximum exit pressure is zero c Comments Active
24 Which of the following is essential for boiler operation? super heater economizer injector safety valve d Comments Active
25 _______ engine requires forward motion through air to produce thrust I.C. Rocket Steam Ramjet d Comments Active
26 TIG welding is preferred for Aluminum Silver Mild steel All of these a Comments Active
27 A rectangular bar with a circular hole is to be made of a material with actual maximum permissible stress of 150 MPa. If stress concentration factor for the configuration is 3.0, what is the nominal average stress for sizing the section? 450 MPa 50 MPa 147 MPa none of these b Stress concentration factor = 3, maximum permissible stress = 150 MPa
Stress developed at irregular section maximum permissible stress \(≤\)
Normal average stress stress concentration factor 150 \(∴\) \(×\) \(≤\)
Normal average stress 3 = 150 \(×\)
Normal average stress = 50 \(∴\)		 Comments Active
28 In Electro-Chemical machining, material removal is due to corrosion erosion fusion ion displacement d Comments Active
29 Thermal efficiency of a stroke engine is ______ with respect to a 4-stroke engine. more less same none of these b Comments Active
30 A 20 tooth pinion meshes with a 63-tooth gear. The gear ratio is 83.5 43.5 0.6 3.15 d Gear ratio is given by
G = = = 3.15 \(\frac{T}{t}\) \(\frac{63}{20}\)		 Comments Active
31 For welding plates of <5mm thickness, the edges require ____ beveling. double V single V no single U c Comments Active
32 Thermal efficiency of Carnot cycle depends on ______temperature only. source sink source & sink none of these c Comments Active
33 The output of a turbine is 300 kW and efficiency is 25%. The input power is 600 kW 1200 kW 900 kW 1500 kW b The efficiency of the turbine is given by:ɳt = 25% = 0.25, Output Power = 300 kW0.25 = \(\frac{300}{Input Power}\)
Input power = = 1200kW \(\frac{300}{0.25}\)		 Comments Active
34 A taper provided on pattern for its easy withdrawal from mould is called _____ allowance. shrinkage machining draft distortion c Comments Active
35 For a cantilever beam of length 2m, under load 1 kN/m, maximum bending moment is 1 kN/m 1 kNm 2 kNm none of these c The maximum bending moment at a cantilever beam subjected to UDL is given by
M = \(\frac{wL^{2}}{2}\)
W = 1 kN/m, L = 2m
M = = 2kN-m \(\frac{1×(2)^{2}}{2}\)		 Comments Active
36 Annealing does not _______ soften the metal relieve stresses refine the grain structure increase the yield point d Comments Active
37 H7 F7 represents a _____fit. interference clearance transition very tight b Here H specifies the hole basis assembly meaning the lower deviation of the hole is zero. F specifies the shafts whose upper deviation is below the zero line. The lower limit of the hole is above the upper limit of the shaft, hence Hole diameter is always bigger than the shaft diameter so the fit will be a clearance fit. Comments Active
38 In a _____ die, both cutting and non-cutting operations are done in a press station in one stroke of ram. compound combination simple progressive b Comments Active
39 Density of mild steel is ____ kg/m3. 10,200 7,860 9,010 none of these b Comments Active
40 Heat transfer occurs due to ______- difference Thermal conductivity Temperature Specific heat Heat flux b Comments Active
41 Two forces 40N and 30N act at right angles to each other on a particle. The resultant force is 1200 N 50 N 50 kg 70 N b R = \(F_{1}^{2}+F_{2}^{2}\)
R = = 50N \(40^{2}+30^{2}\)		 Comments Active
42 Which material has maximum thermal conductivity? Mild steel Aluminum Stainless steel Copper d Comments Active
43 If the tight and slack side tensions in a flat belt running at 1km/minute are 1500N and 100N, the power transmitted is 15.3 kW 10 kW 8.3 kW None of these c Using P = v(T1-T2)
P = (1500 - 1000) 16.68 = 8340 W = 8.3 kW \(×\)
P = 8.3kW		 Comments Active
44 In centrifugal casting method, ____core is used. Sand No Ferrous Non-ferrous b Comments Active
45 Polar moment of inertia of a circular area is \(Ï€D^{4}/64\) \(Ï€D^{4}/32\) \(Ï€D^{2}/4\) None of these b Comments Active
46 A nozzle has velocity head at outlet of 10m. If the jet is vertical, height reached by the steam is 100m 10m \(√\) 10m (1/10) m \(√\) c H = 10m
The velocity of the stream at the nozzle
H = \(\frac{U^{2}}{2g}\)
U2 = 20 g \(×\)
Equation of motion
V2 = U2 - 2gh
Putting the value of U2 in the above equation, also the final velocity at height h will be 0
20g = 2g h \(×\)
H = 10m
With no losses; Velocity head = the height reached by the stream		 Comments Active
47 The shear stress in throat area of weld joint of length L and weld leg h, subject to parallel load P is P/hl 0.707P/hl 1.414P/hl None of these c Comments Active
48 The average cutting speed in machining mild steel by single point tool of HSS is 10 m/ minute 20 m/minute 20 m/minute 40 m/minute c Comments Active
49 If flow rate of water in a pipeline is doubled, then pressure drop will be ____ the original value. same as 2 times 4 times one half of c Comments Active
50 In a centrifugal pump, discharge Q is proportional to N2 N N3 \(√N\) b Comments Active
51 Power transmitted by a shaft running at 700 rpm with torque of 6 kNm= 880 kW 440 kW 220 kW None of these b Given D = 60mm, N = 180rpm, Permissible shear stress = 85 N/mm2
Maximum torque T = max \(τ\) \(×\) \(Z_{P}\)
= 85 = 3604977.5Nmm = 3604.97Nm \(×\) \(\frac{π}{16}×D^{3} = 85×\frac{π}{16}×60^{3}\)
P = = 67.95 kW \(\frac{2Ï€NT}{60}\)		 Comments Active
52 Unit of thermal conductivity is J/kgK W/m2K W/MK None of these c Comments Active
53 Ductility of material is indicated by Ultimate strength Endurance strength Yield strength Elongation d Comments Active
54 Pressure at a depth of 15m under water surface in a dam is approximately 15 bar 1.5 MPa 150 kPa none of these c Height (h) = 15m and density of water () = 103kg/m3 \(ρ\)
The pressure at a depth of 15m is:
Pa = = 150 kPa \(ρgh\)		 Comments Active
55 Petrol engine works on Carnot cycle Rankine cycle Otto cycle Joule cycle c Comments Active
56 Cavitation in a pump is associated with ______pressure. Atmospheric Critical vapor None of these c Comments Active
57 Tensile stress in thin spherical shell subjected to internal pressure is pd/4t pd/2t pd/8t pd/3t a Comments Active
58 Bernoulli’s theorem applies to ____ flow. Incompressible Steady Non-viscous All of these combined d Comments Active
59 A reversible heat engine operates between 300K and 600K. If heat output is 200 kJ, the heat input is 100 kJ 300 kJ 600 kJ 400 kJ d TL = 300K, TH = 600K, Heat output = 200KJ
1 - = 1 - \(\frac{Heat output}{Heat input}\) \(\frac{T_{L}}{T_{H}}\)
1 - = 1 - \(\frac{200}{Heat input} \) \(\frac{300}{600}\)
1 - = \(\frac{200}{Heat input} \) \(\frac{1}{2}\)
Heat input = 400KJ		 Comments Active
60 A tensile load of 500 N is applied to a circular rod diameter of 5mm. The normal stress is approximately 100 N/mm2 25 MPa 100 N/cm2 25 Nmm b F = 500N (tensile), Diameter of circular rod = 5mm
Therefore A = \(\frac{Ï€}{4}d^{2}=\frac{Ï€}{4}5^{2}=\frac{25Ï€}{4}\)
Normal stress() = = = 25.46MPa \(σ\) \(\frac{F}{A}\) \(\frac{500}{\frac{25π}{4}}\)		 Comments Active