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S.No Question Option A Option B Option C Option D Answer Solution Comments Status Action
1 The length of the major axis and minor axis of the ellipse + = 1 are? \(\frac{x^{2}}{144}\) \(\frac{y^{2}}{121}\) 26, 12 12, 11 24, 11 24, 22 Comparing  + = 1 with  + = 1, we find that a = 12, b = 11 and a < b. \(\frac{x^{2}}{144}\) \(\frac{y^{2}}{121}\) \(\frac{x^{2}}{a^{2}}\) \(\frac{y^{2}}{b^{2}}\)
∴ Length of Minor axis = 2a = 24.
The length of the Major axis = 2b = 2		 Comments Active
2 If x = a( - sin), y = a(1-cos), then dy/dx is? \(θ\) \(θ\) \(θ\) Cot(/2) \(θ\) tan(/2) \(θ\) sin(/2) \(θ\) Cos(/2) \(θ\) Given: x = a( - sin), y = a(1-cos) Here, we have to find dy/dx \(θ\) \(θ\) \(θ\)
As we know that, if x = f(t), y = g(t), where t is a parameter, then
X = a(θ - sinθ)
⇒ dx/dθ = a(1 - cosθ)…………(1)
Y = a(1− cosθ)
⇒ dy/dθ = a(0−(−sinθ)) = asinθ……(2)
Dividing (2) and (1) = = = Cot(/2) \(\frac{Dy}{Dx}\) \(\frac{Sinθ}{1 - cosθ}\) \(\frac{2sin(θ/2) × cos(θ/2)}{1 - 1 +2sin^{2}Θ/2}\) \(θ\)		 Comments Active
3 The value of Is? \(limθ→0\frac{sin3θ}{sin4θ}\) -3/4 4/3 3/4 1 c \(LimΘ→0(\frac{Sin3θ}{Θ}×\frac{Θ}{Sin4θ})\)
\(LimΘ→0(\frac{Sin3θ}{Θ}×\frac{1}{Sin4θ/θ})\)
Using product and reciprocal rule of limits
\(LimΘ→0(\frac{3sin3θ}{3θ})\) \(×\frac{1}{LimΘ→0(\frac{4Sin4θ}{4θ})}\)
If \(θ→0\)
Then and approaches to 0 i.e. , \(3θ\) \(4θ\) \(3θ→0\) \(4θ→0\)
3 \(LimΘ→0(\frac{Sin3θ}{3θ})\) \(×\frac{1}{4 LimΘ→0(\frac{Sin4θ}{4θ})}\)
3 1 = \(×\) \(×\) \(\frac{1}{4 × 1}\) \(\frac{3}{4}\)		 Comments Active
4 The value of 20C18 is? 200 190 180 210 b 20C18
We know that, ncr = \(\frac{n!}{r!(n - r)!}\)
So,
20C18 = = = 190 \(\frac{20!}{18!(20 - 18)!}\) \(\frac{20 × 19}{2!}\)		 Comments Active
5 A bag contains 5 red, 4 blue and 3 green balls. Find the probability of randomly drawing a red ball? 1/3 2/3 7/12 5/12 d Total number of balls in the bag = 5 + 4 + 3 = 12
Number of red ball = 5
∴ The probability of getting a red ball = = \(\frac{Number of favourable outcomes}{Total number of outcomes}\) \(\frac{5}{12}\)		 Comments Active
6 First derivative of cot(x)tan(x) is cot2(x) tan2(x) 1 0 d By trigonometric identities: cot A = cos A/sin A = 1/tan A
Therefore, y = t(1/tanx)tanx = 1
So, d y/ d x of constant = 0		 Comments Active
7 Which of the following statements are true w.r.t Hydrostatic forces on surfaces.
1. Total pressure is the force exerted by a static fluid on a surface either plane or curved. This force always acts normal to the surface.
2. In a vertical plane surface submerged in a liquid, the centre of pressure lies below the centre of gravity.
3. The distance of the centre of pressure from the free surface is independent of density of the liquid.		 1,2and 3 1 only 1 & 3 only 1 & 2 only a Comments Active
8 “Equal volumes of all gases at the same temperature and pressure have the same number of molecules” is : Boyles law Charles law Avogadro’s law Daltons law c Comments Active
9 Match the following:
A. Conduction 1. Stefan Boltzmann law
B. Convection 2. Fourier lawC. Radiation 3. Kirchhoff’s law 4. Newton’s law of cooling		 A-2, B-1, C-4 A-2, B-4, C-1 A-2, B-3, C-1 A-4, B-2, C-1 b Comments Active
10 A rigid body shown in the first figure has a mass of 10 kg. It rotates with a uniform angular velocity ‘'. A balancing mass of 20kg is attached as shown in second figure. The percentage increase in mass moment of inertia as result of this addition is \(ω\)
 25% 50% 100% 200% b I1 = mk2
= 102 \(×0.2\)
= 0.4 Kgm2
I2 = m1k12 + m2k22
= 0.4 + 0.2 = 0.6Kgm2
%age increase in MOI = = % \(\frac{0.6-0.4}{0.4}\) \(\frac{0.2}{0.4} = \frac{1}{2} = 50\)		 Comments Active
11 In a 2D CAD software, clockwise circular arc of radius 5, specified from P1(15,10) to P2(10, 15) will have its centre at (10, 10) (15, 10) (15, 15) (10, 15) c Comments Active
12 Routing assists engineers in deciding in advance the flow of material in the plant the method of proper utilization of man power the methods of proper utilization of machines the layout of factory facilities c Routing may be defined as the "selection of proper follow which each part of the product will follow, while being transferred from raw material to finished products. Comments Active
13 Major drawback of EDM process is that it has very high capital cost power consumption is very high Wear takes place at electrode at each spark material removal rate is less c The slow rate of material removal.
The additional time and cost used for creating electrodes for Ram/Sink edm.
Reproducing sharp corners on the work piece is difficult due to electrode wear.		 Comments Active
14 When holes are required to be machined on several faces in small work piece, the jig used is box jig latch jig pot jig post jig a Closed jigs (Box jig) are used when the operations are to be done on more than one side of the piece. Jigs are identified according to the way they are built.  The most commonly used jigs are:
Pot jig
Template jig
Plate jig
Table jig
Sandwich jig
Angle plate jig
Modified angle plate jig
Box jig
Channel jig
Leaf jig
Indexing jig
Solid jig
Post jig
Trunnion jig		 Comments Active
15 Shaving of metals is done in order to Remove burr and improve accuracy Remove excess metal Remove scrap All of the above d Shaving of metals is done in order to remove burr, excess or scrap metal and improve accuracy. Comments Active
16 Degree of freedom for a robot is 10 6 3 5 b Comments Active
17 The index of performance for a machining operation is a function of \(\frac{MRR}{TWR}\) \(\frac{TWR}{MRR}\) \(\frac{MRR-TWR}{MRR}\) \(\frac{TER-MRR}{TWR}\) a Comments Active
18 For IT01 grade, tolerance is expressed as 0.3 + 0.02D 0.5 + 0.12D 0.3 + 0.008D 0.8 + 0.02D c Formula for standard tolerances in grades for basic sizes up to and including 500mm
 Comments Active
19 A centrifugal pump running at 500rpm and at its maximum efficiency is delivering a head of 30m at a flow rate of 60 litres/min. If the rpm is changed to 1000, then the head H in meters and flow rate Q in litres/min at maximum efficiency are estimated to be H = 60, Q = 120 H = 120, Q =120 H = 60, Q = 480 H = 120, Q = 30 b Q N \(∝\)
\(\frac{Q_{1}}{Q_{2}} = \frac{N_{1}}{N_{2}}\)
Q2 = 120
H N2 \(∝\)
\(\frac{H_{1}}{H_{2}} = \frac{N12}{N22}\)
\(\frac{30}{H} = \frac{(500)^{2}}{(1000)^{2}}\)
H2 = 120		 Comments Active
20 In a 5KW cooling capacity refrigeration system operating on a simple vapour compression cycle, the refrigerant enters the evaporator with an enthalpy of 75KJ/Kg and leaves with an enthalpy of 183 KJ/Kg. The enthalpy of the refrigerant after compression is 210 KJ/Kg. The COP and the Power input to compressor is 4, 1.24 KW 4.5, 1.50 KW 4.5, 1.40 KW 4, 1.40 KW a Given: h1 = 75 KJ/Kg
H2 = 183 KJ/Kg
H3 = 210 KJ/Kg

Q = (h2-h1) \(M\)
= = 0.04629 \(M\) \(\frac{5}{108}\)
COP = = = \(\frac{Refrigerating Effect}{Compressor work}\) \(\frac{H_{2}-H_{1}}{H_{3}-H_{2}}\) \(\frac{108}{27} = 4\)
P = ( = 0.04629 27 = 1.25kW \(M\) \(H_{3}-H_{2})\) \(×\)		 Comments Active
21 If the strain energy absorbed in a cantilever beam in bending under its own weight is ‘K’ times greater than the strain energy absorbed in an identical simply supported beam in bending under its own weight, then the magnitude of ‘K’ is 2 4 6 8 c For simply supported beam strain energy,
E1 = \(\frac{W^{2}L^{3}}{240EI}\)
For cantilever beam strain energy,
E2 = \(\frac{W^{2}L^{3}}{40EI}\)
Therefore, = 6 \(\frac{E_{2}}{E_{1}}\)		 Comments Active
22 Volumetric strain for a bar subjected to normal stress on all its surfaces is ( \(Σ_{X}+Σ_{Y}+Σ_{Z})\frac{(1-v)}{2E}\) ( \(Σ_{X}+Σ_{Y}+Σ_{Z})\frac{2v}{E}\) ( \(Σ_{X}+Σ_{Y}+Σ_{Z})\frac{(1+2v)}{E}\) ( \(Σ_{X}+Σ_{Y}+Σ_{Z})\frac{(1-2v)}{E}\) d Comments Active
23 The effort (P) required to lift the load (W) in a screw jack (where is the helix angle andis the angle of friction), is given by \(α \) \( ∅ \) P = W cos(+) \(α\) \(∅\) P = W sin(+) \(α\) \(∅\) P = Wtan(-) \(α\) \(∅\) P = Wtan(+) \(α\) \(∅\) d Comments Active
24 During expansion in steam turbine, entropy Increase exponentially decrease exponentially Increase linearly None of these d Comments Active
25 The loss of head at the entrance to the pipe due to sudden contraction is expressed by \(\frac{0.5V22}{2g}\) \(\frac{(V_{1}-V_{2})^{2}}{2g}\) \(\frac{(V_{1}-V_{2})^{3}}{G}\) \(\frac{V22-V12}{4g}\) a Comments Active
26 Find the melting efficiency for an arc welding process which has a potential of 15 volts and current rating of 250 amperes. Weld has travel speed of 6mm/s for a cross sectional area of 18mm2. Heat transfer efficiency is 0.80 and heat required to melt the base metal is 12J/mm3. 45.0% 43.2% 47.2% 44.5%c b V = 15 volts
I = 250 Av = 6 mm/sA = 18 mm2Hm = Heat required to melt the metalHi = Heat input m = = = = = 43.2% \(ɳ\) \(\frac{H_{M}}{H_{I}}\) \(\frac{12}{\frac{V}{A}×\frac{I}{V}×ɳ}\) \(\frac{12}{\frac{15}{18}×\frac{250}{6}×0.8}\) \(\frac{1296}{3000} = 0.432\)		 Comments Active
27 A metal strip to be rolled from initial wrought thickness of 3.5 mm to a final rolled thickness of 2.5mm in a single pass rolling mill having rolls of 250mm diameter. The strip is 450mm wide. The average co-efficient of friction in the roll gap is 0.08. Assuming plane-strain flow stress of 140MPa for the metal and assuming negligible spreading. The roll separating force F is 320KN 420KN 820.6 KN 165 KN c t = 1mm \( ∆\)
R = 125 mm = 140 MPa \(σ\)
= 0.08 \(Μ\)
Length of contact = \(ROH\)
= = 11.2mm \(125×1 \)
Roll separating force = = 875.9 kN \(\frac{2}{3}Σ(Bl)(1 + \frac{Μl}{4H})\)		 Comments Active
28 The maximum value of reduction in rolling process is = D/2(1-sin) \(∆t\) \(α\) = D(1-sin) \(∆t\) \(α\) = D/2(1-cos) \(∆t\) \(α\) = D/2(1-cos) \(∆t\) \(α/2\) c Comments Active
29 The materials used in the manufacture of thermistors are Oxides of manganese and cobalt Oxides of iron and zinc Carbides of silicon and germanium All of these a Comments Active
30 Rankine’s constant for a mild steel column with both ends hinged is 1/750 1/1600 1/7500 None of the above c Comments Active
31 A thin cylindrical shell of diameter (d), length (l), and thickness (t) is subjected to an internal pressure (P). The ratio of the longitudinal strain to loop strain is m -2/2m-1 2m-1/m-2 m-2/2m+1 m+2/2m+2 a \( \frac{E_{L}}{E_{H}}= \frac{Pd/2te(1/2-μ)}{Pd/4te(2-μ)}\)
= \(\frac{1-2μ}{2 - μ}\)
= \(\frac{1 - 2/m}{2 - 1/m}\)
= \(\frac{M-2/m}{2m - 1/m}\)
= m -2/2m-1		 Comments Active
32 A steel rod of 1m length has to transmit a force of 15kN without stretching more than 1mm. E of steel is 200GPa. Minimum cross sectional area required is 150 mm2 75 m2 150 m2 75 mm2 d Using \(δl = \frac{Pl}{AE}\)
10-3 = \(\frac{15×1000}{A × 200 × 10^{9}}\)
A = 0.000075m2
A = = 75mm2 \(\frac{0.000075}{10^{6}}\)		 Comments Active
33 A differential manometer connected at two points shows a difference in mercury level as 10cm. The difference of pressure at the two points are: (Assume pipe is horizontal, Specific gravity of mercury is 13.6 and fluid in pipe is 0.9, g =10m/s2) 127 N/m2 12700 N/m2 12700 N/mm2 None of the above b PA  + [900 × g × (Y + 0.1)] = PB + (900 × g × Y) + [0.1 × g × 13600]
PA - PB = 13600 × g × 0.1 - 900 × g × 0.1
= 0.1g × 12700 = 12700 N/m2		 Comments Active
34 If a room is to be maintained at 200K while surroundings are at 300K by a refrigeration system using reversed Carnot cycle, Coefficient of Performance (COP) will be: 2 3 0.5 5 a COP = = = 2 \(\frac{Q_{1}}{Q_{1}-Q_{2}}\) \(\frac{200}{100}\) Comments Active
35 Consider the following statements:
Fig 1
Fig 2
Figure 1 represents First angle projection
Figure 2 represents First angle projection
The object assumed to be positioned in between the projection planes and the observer in First angle projection
The object in the third quadrant puts the projection planes between the viewer and the object.		 1,3 and 4 2,3 and 4 1 and 3 only 2 and 4 only b Comments Active
36 Arrange the following in steps followed in powder metallurgy:
1. Metal powdering
2. Blending
3. Compacting
4. Sintering		 1.2.3.4 1,2,4,3 1,4,2,3 1,3,2,4 a Comments Active
37 The stress concentration factor is It is the ratio of maximum stress to the nominal stress It is the ratio of nominal stress to the maximum stress It is the ratio of maximum stress to the endurance limit It is the ratio of nominal stress to the endurance limit a Comments Active
38 The concept of just in Time focuses on eliminating waste reduce machining time reduce labour expenses man power development a IT is an inventory management method whereby labour, material and goods (to be used in manufacturing) are re-filled or scheduled to arrive exactly when needed in the manufacturing process.
The main objective of this method is to reduce inventory holding costs and increase inventory turnover.		 Comments Active
39 Cold worked component are generally subjected to Normalising Tempering Hardening Annealing d Comments Active
40 For refrigerating system work done per Kg of air is 30Kcal and heat extracted per Kg air is 45Kcal. Amount of refrigerant used is 10 Kg. The coefficient of performance of system is 6.52 1.50 10.56 0.67 b COP = = = 1.5 \(\frac{45}{30}\) \(\frac{4.5}{3}\) Comments Active
41 The critical pressure of a liquid is The pressure above which a liquid will explode The pressure above which a liquid will always convert into a vapour. The pressure above which a liquid will remain a liquid. The pressure below which a liquid will always be a vapour form. c Comments Active
42 The cycle generally used for gas turbine is Otto cycle Dual cycle Diesel cycle Brayton cycle d Comments Active
43 If dry steam is heated above saturation temperature, then it is called sensible heat superheating super saturated steam entropy b Comments Active
44 A cylindrical body of cross section area ‘A’, height ‘H’ and the density ‘’ is immersed to a depth of ‘h’ in a liquid of density ‘’ and tied to the bottom with a string. The tension in the string is \(ρ_{s}\) \(ρ\)
 gha \(ρ\) (-)gha \(Ρ_{S}\) \(ρ\) (-)gha \(ρ\) \(Ρ_{S}\) (h-H)ga \(ρ\) \(Ρ_{S}\) d For Vertical equilibrium
Weight of the body + Tension in the string = Buoyant Forcemg + T = Specific weight of water volume of the submerged body \(×\)
sgha + T = gah \(Ρ\) \(ρ\)
T = (h - sh)ga \(ρ\) \(ρ\)		 Comments Active
45 When a venturimeter is used in an inclined position, its reading will show variation with Fluid velocity Fluid density Remains same Decreases c Comments Active
46 Ratio of inertia force to surface tension is known as Weber’s number Mach number Froude number Euler number a Comments Active
47 Which bond gives the softest bond? silicate bond shellac bond vitrified bond all of equal strength a Silicate bond (S): This bonding material is used when the heat generated by grinding must be kept to a minimum. Silicate bonding material releases the abrasive grains more readily than other types of bonding agents. This is the softest bond in grinding wheel. Comments Active
48 Which of the following constituents of steel is softest Ferrite Ledeburite Pearlite Austenite a Comments Active
49 Which of the following is applied to brittle materials maximum principal stress theory maximum principal strain theory maximum strain energy theory maximum shear stress theory a All other theories(ST. Venant’s theory, Guest and Tresca’s Theory, Haigh’s Theory, Mises -Henky theory) are for ductile material except Rankine’s theory i.e. Maximum principal stress theory, which is for brittle material. Comments Active
50 If a number of forces are acting at a point, their resultant will be inclined at an angle with the horizontal, such that \(θ\) tan = \(θ\) \(\frac{H}{V}\) tan = \(θ\) \(\frac{V}{H}\) tan = \(θ\) \(V×H\) tan = \(θ\) \(V+H\) b Comments Active
51 The force exerted on the jet by a moving flat vertical plate, in the direction of plate, is given by the equation: a(VU)2 \(ρ\) -a(V-U)2 \(ρ\) a(V-U) \(ρ\) None of the above b Comments Active
52 Shot peening increases the fatigue life of springs because it results in Alteration of stiffness of spring Residual compression at surface Changes in surface composition Abrasion in surface leads to smooth surface b Shot Peening is a surface enhancement process used to impart compressive residual stresses into fatigue-prone metals. This process increases fatigue strength by delaying the initiation of cracking. Comments Active
53 Endurance limit depends on
1. Material
2. Size3. Surface Finish
4. Type of loading		 1, 2, 3, 4 1, 3, 4 1 and 4 only 1, 2, 3 a Comments Active
54 The stress developed in a thin spherical shell (thickness t and Diameter D) subjected to an internal pressure P is: PD/4t PD/2t PD/t PD/8t a Comments Active
55 Poisson’s ratio of which of the following materials is nearly zero. Rubber Aluminium Cork Steel c Comments Active
56 Which of the following statements are true:
1. Stress and pressure are measured in units of Load/Area.
2. Intensity of pressure at a point is same in all directions whereas stress depends on load and direction.
3. Pressure and Stress are scalar.		 1 and 3 only 1,2,3 1 and 2 only 2 and 3 only c Comments Active
57 Match the following
A. Two wire method1.Interference
B. Optical flat2. Straightness
C. Auto collimator3. Screw threads
D. Clinometers4. Angle w.r.t gravity		 A-1, B-3, C-4, D-2 A-3, B-1, C-2, D-4 A-4, B-3, C-1, D-2 A-3, B-1, C-4, D-2 b Comments Active
58 Match welding defects with causesA. Spatter1.Damp electrodes
B. Lack of penetration2.Less welding current
C. Slag inclusion3. Arc blow
D. Porosity4.Improper cleaning in multi-pass welding		 A-3, B-2, C-4, D-1 A-3, B-2, C-1, D-4 A-4, B-2, C-1, D-3 A-2, B-3, C-4, D-1 a Comments Active
59 Rolling friction is lesser than sliding friction more than sliding friction equal to sliding friction equal to kinetic friction a Comments Active
60 Which one of the following is trapezoidal thread? Acme Square Buttress all of the above a Trapezoidal thread forms are screw thread profiles with trapezoidal outlines. They are the most common forms used for lead screws (power screws). They offer high strength and ease of manufacture. They are typically found where large loads are required, as in a vise or the lead screw of a lathe Comments Active
61 The Mach number of the supersonic flow is between 0.8 and 12 1.2 and 5 5 and 10 none of the above b Comments Active
62 Lame’s theory is associated with thin cylindrical shells thick cylindrical shells direct and bending stresses none of the above b Lame's equation is based on the maximum principal stress theory of failure, as this theory is more suitable for brittle materials, Lame's equation is also applicable to brittle materials like Cast iron or Cast Steel. Comments Active
63 A composite shaft consisting of two stepped portions having spring constants k1 and k2 is held between two rigid supports at the ends. Its equivalent spring constant is \(\frac{K_{1}+K_{2}}{2}\) \(\frac{K_{1}+K_{2}}{K_{1}K_{2}}\) \(\frac{K_{1}K_{2}}{K_{1}+K_{2}}\) \(K_{1}+K_{2}\) d Comments Active
64 In an interchangeable assembly, Shaft of sizes 30+0.030/-0.010 are mated with holes of size 30+0.020/+0.030. Maximum interference and max clearance respectively is: 10 microns, 40 microns 50 microns, 40 microns 40 microns, 10 microns 50 microns, 20 microns a Maximum interference = The maximum limit for shaft - The minimum limit for the hole
= (25 + 0.04) - (25 + 0.02) = 0.02mm = 20microns		 Comments Active
65 The fit on a hole shaft system is specified as G7g6. The type of fit is: Interference Transition Clearance Cannot be determined as basic size is not given c The fundamental deviation of tolerance zone from the basic size is designated by capital letters A, B, C...Z is provided for holes and small letters a, b, c....z is provided for shafts.
Hole diameter is always bigger than the shaft diameter so the fit will be a clearance fit
For hole basis system

For shaft basis system
 Comments Active
66 In a milling machine, cutting tool is held in position by: Chuck Spindle Arbor Tail stock c Comments Active
67 Allowance provided to vertical walls of patterns for easy withdrawal is called: Shrinkage allowance Draft allowance Distortion Camber allowance Rapping allowance b Pattern draft is the taper placed on the pattern surfaces that are parallel to the direction in which the pattern is withdrawn from the mould (that is perpendicular to the parting plane), to allow removal of the pattern without damaging the mould cavity. Comments Active
68 Reciprocation of the cutting tool in shaping machines is accomplished by: Rack pinion mechanism Crank and connecting rod mechanism Cam and cam follower mechanism Oscillating lever mechanism d This is generally accomplished by means of a quick return mechanism. One typical mechanism used in shapers is the quick return mechanism (Oscillating lever mechanism). Comments Active
69 Positive displacement flow meters are……………………flow meters. Variable area flow Differential pressure flow Quantity flow None of these c Comments Active
70 Which of the following welding techniques require a vacuum environment: Ultrasonic welding Laser beam Plasma arc Electron Beam d Electron Beam Welding is a fusion welding in which coalescence is produced by heating the work piece due to impingement of the concentrated electron beam of high kinetic energy on the work piece. As the electron beam impinges the work piece, the kinetic energy of the electron beam converts into thermal energy resulting in melting and even evaporation of the work material. Comments Active
71 Tempering of quenched martensite steel is necessary to improve. Hardness Corrosion resistance Ductility Strength c Tempering is a heat treatment process in which the hardness of a hardened alloy is reduced by the appropriate heat treatment process; for example, steel hardened by the formation of martensite formation can be tempered. Comments Active
72 Match the following
A. Annealing 1. Refines grain structure
B. Nitriding2. Improves hardness of the whole mass
C. Normalizing3. Improves ductility
D. Martempering4. Increases surface hardness(a) A-1, B-2, C-3, D-4		 A-3, B-4, C-1, D-2 A-3, B-4, C-2, D-1 A-1, B-4, C-3, D-2 b Comments Active
73 Francis turbine is best suited for medium head application from 24 to 180m low head installation up to 30m high head installation above 180m all types of heads a Comments Active
74 The stress strain relationship of a Newtonian fluid is linear parabolic Hyperbolic bilinear a Comments Active
75 A steel bar of 6mm is heated from 25 and 60 and it is free to expand. The bar will induce \(℃\) \(℃\) No stress shear stress(c) tensile stress compressive stress a Comments Active
76 The neutral axis of the cross-section of a beam is that axis at which the bending stress is zero minimum maximum infinity a Comments Active
77 Which of the following is the lightest pencil? 2B 1B HB H d Comments Active
78 The designation of sheet of size 594841 is \(×\) A1 A4 A3 A2 a Comments Active
79 A wheel of diameter 10 cm describes 600 revolutions per minute. The angular velocity of the wheel is: 20 rad/s \(π\) 40 rad/s \(π\) 2 rad/s \(π\) 10 rad/s \(π\) a = \(Ω\) \(\frac{Angle rotated}{Time required}\)
= = 20 rad/s \(Ω\) \(\frac{2πN}{60}\) \(π\)		 Comments Active
80 The pair of physical quantities having the same unit is Thrust and weight Thrust and pressure Force and pressure Weight and pressure a Comments Active